Question

A bag contains 4 five rupee coins, 3 two rupee coins and 3 one rupee coins. If 6 coins are drawn from the bag at random, what are the odds in favour of the draw yielding maximum amount?

• A. 1 : 70
• B. 1 : 69
• C. 69 : 70
• D. 70 : 1

Answer 1

Answer: (C)

69 : 70

Answer 2

Total number of coins in the bag = 4 + 3 + 3 = 10
If 6 coins are drawn from the bag at random, then the probability that the draw yields maximum amount is given by,
$=\frac{4^{c4}\times3^{c2}}{10^{c6}}$
$=\frac{1\times3}{210}$
$=\frac{1}{70}$
Odds in favour of the draw $1-\frac{1}{70}=\frac{69}{70}$
Hence, option C is the correct answer.The correct option is (C): 69 : 70