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Question: A bag contains \[3\] red marbles, \[2\] blue marbles, and \[5\] green marbles. What is the probabili...

A bag contains 33 red marbles, 22 blue marbles, and 55 green marbles. What is the probability of randomly selecting a blue marble, then without replacing it, randomly selecting a green marble?

Explanation

Solution

Using the definition of probability, we will first find the probability of randomly selecting a blue marble then we will calculate the probability of randomly selecting a green marble without replacing the blue marble. Then we will multiply both these probabilities to find the probability of randomly selecting a blue marble, then without replacing it, randomly selecting a green marble.

Complete step-by-step answer:
As we know, Probability of an event =number of favourable outcomestotal number of outcomes = \dfrac{{{\text{number of favourable outcomes}}}}{{{\text{total number of outcomes}}}}
In this question, initially we have 33 red marbles, 22 blue marbles, and 55 green marbles.
For the probability of randomly selecting a blue marble, we have
\Rightarrow Number of favourable outcomes =2 = 2
\Rightarrow Total number of outcomes =3+2+5 = 3 + 2 + 5
=10= 10
\Rightarrow Probability of randomly selecting a blue marble =210 = \dfrac{2}{{10}}
Now, for randomly selecting a green marble without replacing, we have a total number of outcomes as 33 red marbles, 11 blue marbles, and 55 green marbles. So, we can write
\Rightarrow Number of favourable outcomes =5 = 5
\Rightarrow Total number of outcomes =3+1+5 = 3 + 1 + 5
=9= 9
\Rightarrow Probability of randomly selecting a green marble =59 = \dfrac{5}{9}
The probability of randomly selecting a blue marble, then without replacing it, randomly selecting a green marble is equal to the product of probability of randomly selecting a blue marble then without replacing probability of randomly selecting a green marble i.e.,
\Rightarrow The probability of randomly selecting a blue marble, then without replacing it, randomly selecting a green marble =210×59 = \dfrac{2}{{10}} \times \dfrac{5}{9}
=19= \dfrac{1}{9}
Therefore, the probability of randomly selecting a blue marble, then without replacing it, randomly selecting a green marble is 19\dfrac{1}{9}.

Note: The probability of an event can only lie between 00 and 11. A probability of 11 indicates that an event certainly takes place, whereas a probability of 00 indicates that an event almost never takes place. We can also write probability as a percentage. Also, note that the sum of probabilities of all possible outcomes is 11.