Question

A bag contains 3 red balls and 5 black balls.A ball is drawn at random from the bag.What is the probability that the ball drawn is (i)red?(ii)not red?

Answer 1

(i) Total number of balls in the bag = 8
$\text{Probability}\ \text{ of}\ \text{ drawing} \ \text{red} \ \text{balls} =\frac{ \text{Number} \ \text{of} \ \text{favourable} \ \text{outcomes}}{ \text{Total}\ \text{ number }\ \text{of} \ \text{total}\ \text{possible} \ \text{outcomes}}$
$=\frac{3}{8}$

(ii) Probability of not getting red ball = 1 - Probability of getting a red ball
$1-\frac{3}{8}=\frac{5}{8}$