Question

A bag contains 3 red 4 blue and 5 yellow colour balls. 3 balls

are drawn one by one in succession without replacement. what is the probability of getting Red, blue, and yellow balls, in same order.

• A. 1/22
• B. 21/22
• C. 3/22
• D. 5/22

Answer 1

Answer: (A)

1/22

Answer 2

Let A, B, C be the event of drawing R, B & Y balls in three consecutive draws with replacement.

P(1) = $\frac { 4 } { 11 }$; P(C/A∩B) = $\frac { 5 } { 10 }$

P(A∩B∩C) = $\frac { 1 } { 4 } \times \frac { 4 } { 11 } \times \frac { 1 } { 2 } = \frac { 1 } { 22 }$ .