Question

A bag contains 3 red 4 blue and 5 yellow colour balls. 3 balls

are drawn one by one in succession without replacement.

Then the probability of getting one red, one blue, one yellow

ball in any order.

• A. 2/11
• B. 3/11
• C. 4/11
• D. 1/11

Answer 1

Answer: (B)

3/11

Answer 2

N(S) = ¹²C₃. n(5) = ³C₁. ⁴C₁. ⁵C₁.

P(5) = $\frac { 60 \times 3 \times 2 } { 12 \times 11 \times 10 } = \frac { 3 } { 11 }$.