Question

A bag contains 2 red, 3 green and 2 blue balls. 2 balls are to be drawn randomly. What is the probability that the balls drawn contain no blue ball?

• A. $\frac{5}{7}$
• B. $\frac{10}{21}$
• C. $\frac{2}{7}$
• D. $\frac{11}{21}$

Answer 1

Answer: (A)

$\frac{5}{7}$

Answer 2

The correct option is (A): $\frac{5}{7}$
Explanation: Explanation: There are 2 red, 3 green, and 2 blue balls in total. The probability of drawing a blue ball is $\frac{2}{7}$. Therefore, the probability that the drawn balls contain no blue balls is$( 1 - \frac{2}{7} = \frac{5}{7} )$