Question

A bag contains 19 tickets numbered from 1 to 19. A ticket is drawn and then another ticket is drawn without replacement. The probability that both the tickets will show even number, is

• A. $\frac { 9 } { 19 }$
• B. $\frac { 8 } { 18 }$
• C. $\frac { 9 } { 18 }$
• D. $\frac { 4 } { 19 }$

Answer 1

Answer: (D)

$\frac { 4 } { 19 }$

Answer 2

The probability of getting an even number in first draw $= \frac { 9 } { 19 }$ . The probability of getting an even number in second draw $= \frac { 8 } { 18 }$. Both are independent event and so required probability $= \frac { 9 } { 19 } \times \frac { 8 } { 18 } = \frac { 4 } { 19 }$