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Question

Mathematics Question on Probability

A bag contains 17 tickets numbered from 1 to 17. A ticket is draw at random, then another ticket is drawn at random, then another ticket is drawn without replacing the first one . The probability that both the tickets may show even numbers is

A

734\frac{7}{34}

B

817\frac{8}{17}

C

716\frac{7}{16}

D

717\frac{7}{17}

Answer

734\frac{7}{34}

Explanation

Solution

Required probability = 817×716=734\frac{8}{17} \times \frac{7}{16} = \frac{7}{34}