Question

A bag contains 17 tickets numbered 1 to 17. A ticket is drawn and replaced, then one more ticket is drawn and replaced. Probability that first number drawn is even and second is odd is

• A. $\frac { 81 } { 289 }$
• B. $\frac { 72 } { 289 }$
• C. $\frac { 64 } { 289 }$
• D. None of these

Answer 1

Answer: (B)

$\frac { 72 } { 289 }$

Answer 2

Let A be the event that first drawn number is even and B be event that the second drawn number is odd.

Total number of even numbers = $\left[ \frac { 17 } { 2 } \right]$ = 8

⇒ P(1) = $\frac { 8 } { 47 }$ and P(2) =$\frac { 9 } { 17 }$⇒ P(A ∩ B) = $\frac { 72 } { 289 }$