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Question: A bag ‘A’ contains 2 white and 3 red balls, another bag ‘B’ contains 4 white and 5 red balls. If one...

A bag ‘A’ contains 2 white and 3 red balls, another bag ‘B’ contains 4 white and 5 red balls. If one ball is drawn at random from one of the bag and it is found to be red, the probability that it was drawn from the bag B is

A

89245\frac { 89 } { 245 }

B

2552\frac { 25 } { 52 }

C

93256\frac { 93 } { 256 }

D

24663\frac { 24 } { 663 }

Answer

2552\frac { 25 } { 52 }

Explanation

Solution

Using Baye’s theorem

Required probability =5/95/9+3/5=2552= \frac { 5 / 9 } { 5 / 9 + 3 / 5 } = \frac { 25 } { 52 }