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Question

Physics Question on Current electricity

A,BA, B and CC are three voltmeters of resistances 4000Ω,6000Ω4000 \, \Omega , 6000 \Omega and 12000Ω12000 \Omega. When a potential difference? is applied between XX and YY, voltmeter readings are VA,VBV_A, V_B and VCV_C. Then

A

VA=VB=VCV_A = V_B = V_C.

B

VA=1.5,VB=3,VCV_A = 1.5 , V_B = 3 , V_C.

C

3VA=2VB=VC3 V_A = 2 V_B = V_C.

D

2VA=VB=VC2 V_A = V_B = V_C.

Answer

VA=VB=VCV_A = V_B = V_C.

Explanation

Solution

6000Ω6000 \, \Omega and 12000Ω 12000 \, \Omega are in parallel,
So, RPY=6000×120006000+12000=4000ΩR_{PY} = \frac{6000 \times 12000}{6000 + 12000} = 4000 \Omega
Here, RXP=RPYR_{XP} = R_{PY}
So, VXP=VPY=V2V_{XP} = V_{PY} = \frac{V}{2}
Hence, VA=VB=VCV_A = V_B = V_C