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Question: A (aq)\(\rightarrow\) B (aq) + C (aq) is a first order reaction. Time t \(\infty\) Moles of reagen...

A (aq)\rightarrow B (aq) + C (aq) is a first order reaction.

Time t \infty

Moles of reagent n1 n2

Reaction progress is measure with the help of titration of reagent ‘R’. If all A, B and C reacted with reagent and have ‘n’ factors [nfactors;eq.wt.=mol.wtn]\left\lbrack nfactors;eq.wt. = \frac{mol.wt}{n} \right\rbrackin the ratio of 1 : 2 : 3 with the reagent. The k in terms of t, n1 and n2 is :

A

k=1tIn(n2n2n1)k = \frac{1}{t}In\left( \frac{n_{2}}{n_{2} - n_{1}} \right)

B

k=1tIn(2n2n2n1)k = \frac{1}{t}In\left( \frac{2n_{2}}{n_{2} - n_{1}} \right)

C

k=1tIn(4n2n2n1)k = \frac{1}{t}In\left( \frac{4n_{2}}{n_{2} - n_{1}} \right)

D

k=1tIn(4n25(n2n1))k = \frac{1}{t}In\left( \frac{4n_{2}}{5\left( n_{2} - n_{1} \right)} \right)

Answer

k=1tIn(4n25(n2n1))k = \frac{1}{t}In\left( \frac{4n_{2}}{5\left( n_{2} - n_{1} \right)} \right)

Explanation

Solution

A (aq) \longrightarrow B (aq) + C (aq)

t=0 a 0 0

t=t a–x x x

t= 0 a a

(a – x) + 2x + 3x \propto n1

a + 4x \propto n1.....(i)

2a + 3a \propto n2

an25a \propto \frac{n_{2}}{5}.....(ii)

k=1tIn[aax]k = \frac{1}{t}In\left\lbrack \frac{a}{a - x} \right\rbrack