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Chemistry Question on Haloalkanes and Haloarenes

‘A’ and ‘B’ respectively are: A→(2)Zn−H2O(1)O3A\xrightarrow[(2)Zn-H_2O]{(1)O_3}
Ethane−1,2−dicarbaldehyde+Glyoxal/OxaldehydeEthane-1, 2-dicarbaldehyde + Glyoxal/Oxaldehyde
B→(2)Zn−H2O(1)O35−oxohexanalB \xrightarrow[(2)Zn-H_2O]{(1)O_3} 5 - oxohexanal

A

1−methylcyclohex−1,3−diene  &  cyclopentene1-methylcyclohex-1, 3-diene \;\& \;cyclopentene

B

Cyclohex−1,3−diene  &  cyclopenteneCyclohex-1, 3-diene \;\& \;cyclopentene

C

1−methylcyclohex−1,4−diene  &  1−methylcyclo−pent−ene1-methylcyclohex-1, 4-diene \;\& \;1-methylcyclo-pent-ene

D

Cyclohex−1,3−diene  &  1−methylcyclopent−1−eneCyclohex-1, 3-diene \;\&\; 1-methylcyclopent-1-ene

Answer

Cyclohex−1,3−diene  &  1−methylcyclopent−1−eneCyclohex-1, 3-diene \;\&\; 1-methylcyclopent-1-ene

Explanation

Solution

Solution :

Cyclohex-1, 3-diene & 1-methylcyclopent-1-ene