Question

A and B are two railway stations 90 km apart. A train leaves A at 9:00 am, heading towards B at a speed of 40 km/hr. Another train leaves B at 10:30 am, heading towards A at a speed of 20 km/hr. The trains meet each other at

• A. 11 : 45 am
• B. 10 : 45 am
• C. 11 : 20 am
• D. 11 : 00 am

Answer 1

Answer: (D)

11 : 00 am

Answer 2

The correct answer is (D): $11 : 00 am$

The distance travelled by $A$ before $B$ starts his journey = $40×1.5 = 60$

The time taken by them to meet each other = $\frac{90-60}{40+20} = \frac{30}{60} = 0.5$ hours

Required answer = $10:30 \;a.m. + 30 \;min = 11:00 \;a.m.$