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Question

Physics Question on Refraction of Light

A and B are two parallel sided transparent slabs of refractive indices n1_1 and n2_2 respectively. A ray is incident at an angle θ\theta on the surface of separation of A and B, and after refraction from B into air grazes the surface of B. Then

A

sinθ=1n2sin \theta =\frac{1}{n^{2}}

B

sinθ=1n1sin \theta =\frac{1}{n_{1}}

C

sinθ=n2n1sin \theta =\frac{n_{2}}{n_{1}}

D

sinθ=n1n2sin \theta =\frac{n_{1}}{n_{2}}

Answer

sinθ=1n1sin \theta =\frac{1}{n_{1}}

Explanation

Solution

From snell?s law
n1sinθ=1n_{1} sin \theta =1
sinθ=1n1sin \theta =\frac{1}{n_{1}}