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Question: A and B are two events such that P (1)= 0.8, P(2)=0.6 and \(P ( A \cap B ) = 0.5\) then the value ...

A and B are two events such that P (1)= 0.8, P(2)=0.6 and P(AB)=0.5P ( A \cap B ) = 0.5 then the value of P(A/B)P ( A / B ) is

A

56\frac { 5 } { 6 }

B

58\frac { 5 } { 8 }

C

910\frac { 9 } { 10 }

D

None of these

Answer

56\frac { 5 } { 6 }

Explanation

Solution

P(AB)=P(AB)P(B)=0.50.6=56P \left( \frac { A } { B } \right) = \frac { P ( A \cap B ) } { P ( B ) } = \frac { 0.5 } { 0.6 } = \frac { 5 } { 6 }.