Question

A and B are the points (2, 0) and (0, 2) respectively. The coordinates of the point P on the line 2x + 3y + 1 = 0 such that |PA – PB| is minimum, will be :

• A. (7, – 5)
• B. $\left( - \frac { 1 } { 5 } , - \frac { 1 } { 5 } \right)$
• C. (–7, 5)
• D. $\left( - \frac { 1 } { 5 } , \frac { 1 } { 5 } \right)$

Answer 1

Answer: (A)

(7, – 5)

Answer 2

|PA – PB| is minimum

Equation of L is

x + y = 2

Now P is point of intersection of L and

2x + 3y + 1 = 0