Question

A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine

1. P(not A)
2. P (not B)
3. P(A or B)

Answer 1

It is given that P(A) = 0.42, P(B) = 0.48, P(A and B) = 0.16

(i) P(not A) = 1 - P(A) = 1 - 0.42 = 0.58

(ii) P(not B) = 1 - P(B) = 1 - 0.48 = 0.52

(iii) We know that P(A or B) = P(A) + P(B) - P(A and B)
∴ P(A or B) = 0.42 + 0.48 - 0.16 = 0.74