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Question: A 90 cm long soleniod has six layers of windings of 450 turns each. If the diameter of solenoid is 2...

A 90 cm long soleniod has six layers of windings of 450 turns each. If the diameter of solenoid is 2.2 cm and current carried is 6 A, then the magnitude of field inside the solenoid, near its centre is

A

50πG50 \pi \mathrm { G }

B

C

72πG72 \pi \mathrm { G }

D

80πG80 \pi \mathrm { G }

Answer

72πG72 \pi \mathrm { G }

Explanation

Solution

For six layers of windings the total number of turns

=6×450=2700= 6 \times 450 = 2700

Now number of turns per unit length

Then the field inside the solenoid near the centre

B=μ0nI=4π×107×3000×6=72π×104 T\mathrm { B } = \mu _ { 0 } \mathrm { nI } = 4 \pi \times 10 ^ { - 7 } \times 3000 \times 6 = 72 \pi \times 10 ^ { - 4 } \mathrm {~T}

=72πG= 72 \pi \mathrm { G }