Question

A 750 Hz, 20 volt source is connected to a resistance of 100 ohm, an inductance of 0.1803 henry and a capacitance of 10µF, all in series. The time in which the resistance (thermal capacity = 2 joule/ŗC) will get heated by 10⁰C is –

• A. 348 sec
• B. 328 sec
• C. 248 sec
• D. 228 sec

Answer 1

Answer: (A)

348 sec

Answer 2

I_rms = $\frac{E_{rms}}{Z}$ = $\frac{E_{v}}{\sqrt{R^{2} + \left( \omega L–\frac{1}{\omega C} \right)^{2}}}$

= 0.023 amp

\ H = I²Rt = 2 × 10

or (0.023)² × 100 × t = 20

\ t = $\frac{20}{(0.023)^{2} \times 100}$ = 348 sec