Question

A $60\,\mu F$ capacitor is connected to a $110\,V (rms)$, $60\,Hz$ ac supply, the net power absorbed by the circuit in one complete cycle is

• A. $5\,W$
• B. $10\,W$
• C. $15\,W$
• D. zero

Answer 1

Answer: (D)

zero

Answer 2

As $P=V_{rms}\,I_{rms}\,I_{rms}\,cos\,\phi$ In a pure capacitance circuit, the phase difference between alternating voltage and current is $\pi /2$. Hence $P = V_{rms}\,I_{rms}\,cos\,90^? = 0$.