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Question

Physics Question on Alternating current

A 60μF60\,\mu F capacitor is connected to a 110V(rms)110\,V (rms), 60Hz60\,Hz ac supply. The rms value of current in the circuit is

A

1.49A1.49\,A

B

14.9A14.9\,A

C

2.49A2.49\,A

D

24.9A24.9\,A

Answer

2.49A2.49\,A

Explanation

Solution

Capacitor C =60μF=60 \mu F Peak voltage Vrms=110VV _{ rms }=110 V ACAC supply freqency f=60Hzf =60 Hz Irms=VrmsXCI _{ rms }=\frac{ V _{ rms }}{ X _{ C }} Capacitive Reactance XC=1wCX _{ C }=\frac{1}{ wC } Irms=Vrms1wCI _{ rms }=\frac{ V _{ rms }}{\frac{1}{ wC }} Irms=Vrms2πfC\therefore I _{ rms }= V _{ rms } 2 \pi fC Irms=110×2π×60×60×106\therefore I _{ rms }=110 \times 2 \pi \times 60 \times 60 \times 10^{-6} Irms=2.49A\therefore I _{ rms }=2.49 \,A Thus the rms value of current in the circuit is 2.49A2.49 \,A