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Question

Physics Question on Alternating Current

A 60 μF capacitor is connected to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit

Answer

Capacitance of capacitor, C = 60 µF = 60 × 10−6 F

Supply voltage, V = 110 V

Frequency, ν = 60 Hz

Angular frequency, ω= 2 ν

Capacitive reactance,

XC=1ωC=12πVC=12πX60X60X106ΩXC=\frac{1}{ωC}=\frac{1}{2πVC}=\frac{1}{2πX60X60X10^-6}Ω

rms value of current is given as:

I=VXC=2202πX60X60X106=2.49AI=\frac{V}{X_C}=\frac{220}{2πX60X60X10^{-6}}=2.49 A

Hence, the rms value of current is 2.49 A.