Question

A 6 volt battery is connected to the terminals of a three metre long wire of uniform thickness and resistance of 100 ohm. The difference of potential between two points on the wire separated by a distance of 50 cm will be –

• A. 2 volt
• B. 3 volt
• C. 1 volt
• D. 1.5 volt

Answer 1

Answer: (C)

1 volt

Answer 2

V_AB = E  

Potential gradient Κ =  $\frac{V_{AB}}{L}$ = $\frac{E}{L}$

∴ Potential difference across length l is V = Kl

= $\frac{E}{L}$ × l = $\frac{6}{3}$× 0.5 = 1 volt