Solveeit Logo
Login

Question

Question: A 5g bullet was fixed horizontal into a 1.2 kg wooden block resting on a wooden surface. The coeffic...

A 5g bullet was fixed horizontal into a 1.2 kg wooden block resting on a wooden surface. The coefficient of kinetic friction between the block and surface is 0.2. The bullet remained embedded in the block. The block was found to slide 0.23 m along the surface before stopping. Find initial speed of bullet.

A

241 ms-1

B

229 ms-1

C

221 ms-1

D

201 ms-1

Answer

229 ms-1

Explanation

Solution

v' = 5v1205=v241\frac{5v}{1205} = \frac{v}{241} and v'2 = 2 as

∴ (v241)2\left( \frac{v}{241} \right)^{2}= 2 × .2 × .23 × 10

v = 241×241×.92=229ms−1\sqrt{241 \times 241 \times .92} = 229ms^{- 1}