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Question: A 500 kg horse pulls a cart of mass 1500 kg along a level road with an acceleration of \(1 \mathrm ...

A 500 kg horse pulls a cart of mass 1500 kg along a level road with an acceleration of 1 ms−21 \mathrm {~ms} ^ { - 2 } . If the coefficient of sliding friction is 0.2, then the force exerted by the horse in forward direction is

A

3000 N

B

4000 N

C

5000 N

D

6000 N

Answer

6000 N

Explanation

Solution

Net force in forward direction = Accelerating force + Friction

=ma+μmg=m(a+μg)=(1500+500)(1+0.2×10)= m a + \mu m g = m ( a + \mu g ) = ( 1500 + 500 ) ( 1 + 0.2 \times 10 )

=2000×3=6000 N= 2000 \times 3 = 6000 \mathrm {~N}