Question

A $50\,\Omega$ galvanometer is shunted by a resistance of $5\,\Omega .$ The percentage of the total current, which passes through the galvanometer is

• A. 0.081
• B. 0.101
• C. 0.111
• D. 0.091

Answer 1

Answer: (D)

0.091

Answer 2

Suppose, G is the resistance of galvanometer and ${{I}_{g}}$ is the current for full scale deflection. If $\text{I}$ is the maximum current, then ${{I}_{g}}\times G=(I-{{I}_{g}})S$ Given. $G=50\,\Omega$ and $S=5\,\Omega$ $\therefore$ $\frac{{{I}_{g}}}{I}=\frac{S}{G+S}=\frac{5}{50+5}=\frac{5}{55}=\frac{1}{11}$ $\Rightarrow$ ${{I}_{g}}=\frac{I}{11}$ or $\frac{{{I}_{g}}}{I}=\frac{1}{11}$ or $\frac{{{I}_{g}}}{I}$