Question
Question: A 50 MHz sky wave takes 4.04 ms to reach a receiver via re-transmission from a satellite 600 km abov...
A 50 MHz sky wave takes 4.04 ms to reach a receiver via re-transmission from a satellite 600 km above earth's surface. Assuming re-transmission time by satellite negligible, find the distance between source and receiver.
A
606 km
B
170 km
C
340 km
D
280 km
Answer
170 km
Explanation
Solution
: here
Total time taken
t=4.04ms=4.04×10−3s
Let x be the distance of satellite from the surface of earth
Total time taken (t)
=Speedofelectromagneticwave(c)Totaldistancetravelled(2x)
∴x=2ct=2(3×108)(4.04×10−3)=6.06×105m=606kmLet T be the source of electromagnetic waves (i.e. transmitter), R be receiver and S be satellite at locations as shown in figure
}{= 7236 }{\therefore d = 85.06km}$$ Distance between source and receiver <img src="https://cdn.pureessence.tech/canvas_521.png?top_left_x=203&top_left_y=600&width=148&height=170" style="width:0.96528in;height:1.125in" /> $$= 2d = 2 \times 85.06 = 170km$$