Question

A 50 mH coil carries a current of 2 ampere. The energy stored in joules is

• A. 1
• B. 0.1
• C. 0.05
• D. 0.5

Answer 1

Answer: (B)

0.1

Answer 2

Energy stored

$E = \frac{1}{2}Li^{2} = \frac{1}{2} \times 50 \times 10^{- 3} \times 4 = 0.1\mspace{6mu} J$