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Question: A 50 Hz ac source of 20 volts is connected across R and C as shown in figure. The voltage across R i...

A 50 Hz ac source of 20 volts is connected across R and C as shown in figure. The voltage across R is 12 volt. The voltage across C is –

A

8 V

B

16 V

C

10 V

D

Not possible to determine unless values of R and C are given

Answer

16 V

Explanation

Solution

Vsource = VR2+VC2\sqrt{V_{R}^{2} + V_{C}^{2}}

\ VC = VSource2VR2\sqrt{V_{Source}^{2}–V_{R}^{2}}

= (20)2(12)2\sqrt{(20)^{2}–(12)^{2}}

= 16 V