Solveeit Logo

Question

Physics Question on Electromagnetic induction

A 50HzAC50\, Hz \,AC current of peak value 2A2\, A flows through one of the pair of coils. If the mutual inductance between the pair of coils is 150mH150\, mH, then the peak value of voltage induced in the second coil is

A

30πV30\,\pi V

B

60πV60\,\pi V

C

15πV15\,\pi V

D

300πV300\,\pi V

Answer

30πV30\,\pi V

Explanation

Solution

M=150×103HM=150\times {{10}^{-3}}H i=2Ai=2A f=50Hzf=50\,Hz
Induced voltage, e=dϕdte=\frac{d\phi }{dt}
=ddt(Mi)=ddt(Mi0sinωt)ωcosωt=\frac{d}{dt}(Mi)=\frac{d}{dt}(M{{i}_{0}}\sin \omega t)\omega \cos \omega t e is maximum when cosωt=1\cos \omega t=1
\therefore e=Mi0ωe=M{{i}_{0}}\omega
=150×103×i×2πf=150\times {{10}^{-3}}\times i\times 2\pi f
=150×103×2×2π×50=150\times {{10}^{-3}}\times 2\times 2\pi \times 50
=30 πV=30\text{ }\pi V