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Question

Question: A \(4\mu F\) conductor is charged to 400 volts and then its plates are joined through a resistance o...

A 4μF4\mu F conductor is charged to 400 volts and then its plates are joined through a resistance of 1kΩ1k\Omega. The heat produced in the resistance is

A

0.16 J

B

1.28 J

C

0.64 J

D

0.32 J

Answer

0.32 J

Explanation

Solution

Heat produced = Energy stored in capacitor

=12CV2=12×4×106×(400)2=0.32J= \frac{1}{2}CV^{2} = \frac{1}{2} \times 4 \times 10^{- 6} \times (400)^{2} = 0.32J