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Question

Physics Question on Alternating current

A 44mH44\,mH inductor is connected to 220V220\,V, 50Hz50\,Hz ac supply. The rms value of the current in the circuit is

A

12.8A12.8\,A

B

13.6A13.6\,A

C

15.9A15.9\,A

D

19.5A19.5\,A

Answer

15.9A15.9\,A

Explanation

Solution

Here, L=44mH=44×103HL = 44\,mH = 44 \times 10^{-3}\, H Vrms=220V,V_{rms} = 220\,V, υ=50Hz\upsilon=50\,Hz The inductive reactance is XL=ωLX_{L}=\omega L =2πυL=2×3.14×50×44×103=2\pi\upsilon L=2\times3.14\times50\times44\times10^{-3} =13.82Ω=13.82\,\Omega Irms=VrmsXL\therefore I_{rms}=\frac{V_{rms}}{X_{L}} =22013.82=\frac{220}{13.82} =15.9A=15.9\,A