Question
Physics Question on Alternating current
A 44mH inductor is connected to 220V, 50Hz ac supply. The rms value of the current in the circuit is
A
12.8A
B
13.6A
C
15.9A
D
19.5A
Answer
15.9A
Explanation
Solution
Here, L=44mH=44×10−3H Vrms=220V, υ=50Hz The inductive reactance is XL=ωL =2πυL=2×3.14×50×44×10−3 =13.82Ω ∴Irms=XLVrms =13.82220 =15.9A