Question

A $400\, mg$ iron capsule contains $100\, mg$ of ferrous fumarate, $(CHCOO)_2Fe$. The percentage of iron present in it, is approximately

• A. 0.33
• B. 0.25
• C. 0.14
• D. 0.08

Answer 1

Answer: (D)

0.08

Answer 2

Molecular wt. of $(CHCOO)_2Fe = 170$ Fe present in 100 mg of $(CHCOO)_2Fe$ $=\frac{56}{170}\times100\,mg=32.9\,mg$ This is present in $400\, mg$ of the capsule $\therefore \%$ of Fe in the capsule $=\frac{32.9}{400}\times100=8.2$