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Question

Physics Question on Alternating current

A 40μF40\, \mu\,F capacitor is connected to a 200V200\,V,50Hz50\,Hz ac supply. The rms value of the current in the circuit is, nearly :

A

1. 7 A

B

2. 05 A

C

2. 5 A

D

25. 1 A

Answer

2. 5 A

Explanation

Solution

The correct option is(C):2. 5 A

The rms value of the current
irms=Cωεrmsi_{\text{rms}}=C\,\omega\,\varepsilon_{\text{rms}}
C=40×106FC=40\times10^{-6}F
ω=2πf=100π\omega=2\pi\,f =100\,\pi
εrms=200V\varepsilon_{\text{rms}}=200\,V
irms=200×40×106×2π×50\therefore i_{\text{rms}}=200\times40\times10^{-6}\times2\pi\times50
=2.5A=2.5\,A