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Question: A 40 mF capacitor is a defibrillator is charged to 3000 V. The energy stored in the capacitor is sen...

A 40 mF capacitor is a defibrillator is charged to 3000 V. The energy stored in the capacitor is sent through the patient during a pulse of duration 2 ms. The power delivered to the patient is-

A

45 kW

B

90 kW

C

180 Kw

D

360 kW

Answer

90 kW

Explanation

Solution

Power = P =  Energy  time =12CV2t\frac { \text { Energy } } { \text { time } } = \frac { \frac { 1 } { 2 } \mathrm { CV } ^ { 2 } } { \mathrm { t } }

= CV22t=40×10−6×9×1062×2×10−3\frac { \mathrm { CV } ^ { 2 } } { 2 \mathrm { t } } = \frac { 40 \times 10 ^ { - 6 } \times 9 \times 10 ^ { 6 } } { 2 \times 2 \times 10 ^ { - 3 } }

= 90 × 1000 watt = 90 Kw