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Question: A 4 kg block A is placed on the top of a 8 kg block B which rests on a smooth table. A just slips on...

A 4 kg block A is placed on the top of a 8 kg block B which rests on a smooth table. A just slips on B when a force of 12 N is applied on A. Then the maximum horizontal force on B to make both A and B move together, is

A

12 N

B

24 N

C

36 N

D

48 N

Answer

36 N

Explanation

Solution

Maximum friction i.e. limiting friction between A and B, FlF_{l} = 12 N.

If F is the maximum value of force applied on lower body such that both body move together

It means Pseudo force on upper body is just equal to limiting friction

F=FlF' = F_{l}m(Fm+M)=m \left( \frac { F } { m + M } \right) = (44+8)F=12\left( \frac{4}{4 + 8} \right)F = 12 F=36N.\therefore F = 36N.