Question

A 3d-electron having spin quantum number, $s=+\frac{1}{2},$ can have a magnetic quantum number:

• A. 3
• B. -2
• C. 4
• D. -3

Answer 1

Answer: (B)

-2

Answer 2

For d-sub-shell, the value of azimuthal quantum number $(l)=2.$ $\therefore$ Total number of values of $m=(2l+1)=5$ These five values of m are -2, -1, 0, +1 and +2. Hence, 3d-electron can have -2 magnetic quantum number. (-3 and +3 values are possible only for f-orbitals)