Question

A 300 W carrier is modulated to a depth 75%. The total power in the modulated wave is

• A. 200 W
• B. 284 W
• C. 320 W
• D. 384 W

Answer 1

Answer: (D)

384 W

Answer 2

: $p_{c} = 300W,\mu = 75\% = 0.75$

As $p_{t} = p_{c}\left( 1 + \frac{\mu^{2}}{2} \right)$

Or $p_{t} = 300\left( 1 + \frac{(0.75)^{2}}{2} \right) = 384W$