Question

A 30 gm bullet initially travelling at 120 m/s penetrates 12 cm into a wooden block. The average resistance exerted by the wooden block is

• A. 2850N
• B. 2200 N
• C. 2000
• D. 1800 N

Answer 1

Answer: (D)

1800 N

Answer 2

$F = \frac{m(u^{2} - v^{2})}{2S} = \frac{30 \times 10^{- 3} \times (120)^{2}}{2 \times 12 \times 10^{- 2}} = 1800N$