Question

A (3, 1), B (6, 5) and C (x, y) are three points such that angle ACB is a right angle and the area of triangle ABC = 7sq. unit. then the number of such points C is-

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (A)

0

Answer 2

AB = $\sqrt{(3–6)^{2} + (1–5)^{2}}$ = $\sqrt{9 + 16}$ = 5

2r = 5 Ž r = 5/2 = 2.5 Ž DABC = 7

$\frac{1}{2}$× AB × h = 7 Ž h = $\frac{2 \times 7}{5}$ Ž h = 2.8

h > r ; which is not possible hence no point