Question

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

Answer 1

Length of the wire, $l = 3\,cm = 0.03\,m$
Current flowing in the wire, $I = 10\,A$
Magnetic field, $B = 0.27 \,T$
Angle between the current and magnetic field, $θ = 90°$
Magnetic force exerted on the wire is given as:
$F= BISinθ$
$=0.27 × 10 × 0.03 \,sin90°$
$= 8.1 × 10^{–2} N$
Hence, the magnetic force on the wire is $8.1 × 10^{–2} N$. The direction of the force can be obtained from Fleming’s left hand rule.