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Question: A 2V battery is connected across AB as shown in the figure. The value of the current supplied by the...

A 2V battery is connected across AB as shown in the figure. The value of the current supplied by the battery when in one case, battery’s positive terminal is connected to A and in other case when positive terminal of battery is connected to B will respectively be

A. 0.2 A and 0.1 A
B. 0.1 A and 0.2 A
C. 0.2 A and 0.4 A
D. 0.4 A and 0.2 A

Explanation

Solution

When the positive terminal of battery is connected to A diode D1{D}_{1} gets forward biased and current flows through it. To find the current flowing through it use Ohm's law. Substitute the values and find the current flowing through the diode D1{D}_{1}. Similarly, when a positive terminal is connected to B, diode D2{D}_{2} gets forward biased current flows through it. Again, use the formula for Ohm's law and find the current flowing through D2{D}_{2}.

Formula used: V=IRV=IR

Complete step by step solution:
Given: Voltage (V)= 2V
Resistance R1=5Ω{R}_{1}= 5 \Omega
Resistance R2=10Ω{R}_{2}= 10 \Omega
Case.1) When the positive terminal of the battery is connected to A, the diode D1{D}_{1} gets forward biased while the diode D2{D}_{2} gets reverse biased. Hence, the current will pass only through diode D1{D}_{1}.
According to Ohm's law,
V=IRV=IR
Current passing through diode D1{D}_{1} is given by,
V=IR1V= I {R}_{1}
Substituting values in above equation we get,
2=I×52= I \times 5
I=25\Rightarrow I= \dfrac {2}{5}
I=0.4A\Rightarrow I= 0.4 A
Thus, 0.4 current will flow through the diode D1{D}_{1} when the positive terminal of the battery is connected to A.
Case.2) When the positive terminal of the battery is connected to B, the diode D2{D}_{2 } gets forward biased while the diode D1{D}_{1} gets reverse biased. Hence, the current will pass only through diode D2{D}_{2}.
According to Ohm's law,
V=IRV=IR
Current passing through diode D2{D}_{2} is given by,
V=IR2V= I {R}_{2}
Substituting values in above equation we get,
2=I×102= I \times 10
I=210\Rightarrow I= \dfrac {2}{10}
I=0.2A\Rightarrow I= 0.2 A
Thus, 0.2 current will flow through the diode D2{D}_{2 } when the positive terminal of the battery is connected to B.

So, the correct answer is “Option D”.

Note: To answer these types of questions, students must know how the current flows through a diode when a positive or negative terminal of a battery is connected to it. They should also know the concept of forward bias and reverse bias. Students generally forget the anode and cathode side of a diode so they should remember that as well. In most of the diodes, current flows only when a positive voltage is given to the anode.