Question: A 2kg copper block is heated to 500<sup>0</sup>C and then it is placed on a large block of ice at 0<...

Question

A 2kg copper block is heated to 500⁰C and then it is placed on a large block of ice at 0⁰C. If the specific heat capacity of copper is 400 J/kg/⁰C and latent heat of water is 3.5 × 10⁵ J/kg. The amount of ice that can melt is –

Answer 1

Solution

Heat lost by copper = heat gain by ice

2 × 400 × [500 –0] = x × 3.5 × 10⁵

\ x = $\frac{8}{7}$ kg