Question

A 280 ohm electric bulb is connected to 200V electric line. The peak value of current in the bulb will be

• A. About one ampere
• B. Zero
• C. About two ampere
• D. About four ampere

Answer 1

Answer: (A)

About one ampere

Answer 2

$i_{rms} = \frac{200}{280} = \frac{5}{7}A.$ So $i_{0} = i_{rms} \times \sqrt{2} = \frac{5}{7} \times \sqrt{2} \approx 1A.$