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Question: A 220 V, 50 Hz ac source is connected to an inductance of 0.2 H and a resistance of 20 ohm in series...

A 220 V, 50 Hz ac source is connected to an inductance of 0.2 H and a resistance of 20 ohm in series. What is the current in the circuit

A

10 A

B

5 A

C

33.3 A

D

3.33 A

Answer

3.33 A

Explanation

Solution

i=220(20)2+(2×π×50×0.2)2=22066=3.33Ai = \frac{220}{\sqrt{(20)^{2} + (2 \times \pi \times 50 \times 0.2)^{2}}} = \frac{220}{66} = 3.33A