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Question: A 200*g* golf ball is moving with a speed of 5 *m* per hour. The associated wave length is \((h = 6....

A 200g golf ball is moving with a speed of 5 m per hour. The associated wave length is (h=6.625×10−34J−sec)(h = 6.625 \times 10^{- 34}J - sec)

A

10−10m10^{- 10}m

B

10−20m10^{- 20}m

C

10−30m10^{- 30}m

D

10−40m10^{- 40}m

Answer

10−30m10^{- 30}m

Explanation

Solution

λ=hmv=6.625×10−340.2kg×560×60ms−1=10−30m\lambda = \frac{h}{mv} = \frac{6.625 \times 10^{- 34}}{0.2kg \times \frac{5}{60 \times 60ms^{- 1}}} = 10^{- 30}m.