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Question

Question: A 200 turn closely wound circular coil of radius 15 cm carries a current 4 of A. The magnetic moment...

A 200 turn closely wound circular coil of radius 15 cm carries a current 4 of A. The magnetic moment of this coil is

A

36.5 A m236.5 \mathrm {~A} \mathrm {~m} ^ { 2 }

B

56.5 A m256.5 \mathrm {~A} \mathrm {~m} ^ { 2 } A

C

66.5 A m266.5 \mathrm {~A} \mathrm {~m} ^ { 2 }

D

108 A m2108 \mathrm {~A} \mathrm {~m} ^ { 2 }

Answer

56.5 A m256.5 \mathrm {~A} \mathrm {~m} ^ { 2 } A

Explanation

Solution

The magnetic moment is given by

=200×4×3.14×(15×102)2= 200 \times 4 \times 3.14 \times \left( 15 \times 10 ^ { - 2 } \right) ^ { 2 }

=200×4×3.14×15×15×104=56.5Am2= 200 \times 4 \times 3.14 \times 15 \times 15 \times 10 ^ { - 4 } = 56.5 \mathrm { Am } ^ { 2 }