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Question: A 20 kg block is initially at rest on a rough horizontal surface. A horizontal force of 75 N is requ...

A 20 kg block is initially at rest on a rough horizontal surface. A horizontal force of 75 N is required to set the block in motion. After it is in motion, a horizontal force of 60 N is required to keep the block moving with constant speed. The coefficient of static friction is

A

0.38

B

0.44

C

0.52

D

0.60

Answer

0.38

Explanation

Solution

Coefficient of friction

μs=FlR=75mg=7520×9.8\mu _ { s } = \frac { F _ { l } } { R } = \frac { 75 } { m g } = \frac { 75 } { 20 \times 9.8 } =0.38= 0.38