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Question: A 2 volt battery, a \(15 \Omega\) resistor and a potentiometer of 100 cm length, all are connected...

A 2 volt battery, a 15Ω15 \Omega resistor and a potentiometer of 100 cm length, all are connected in series. If the resistance of potentiometer wire is 5Ω5 \Omega, then the potential gradient of the potentiometer wire is

A

0.005 V/cm

B

0.05 V/cm

C

0.02 V/cm

D

0.2 V/cm

Answer

0.005 V/cm

Explanation

Solution

Potential gradient =e(R+Rh+r)⋅RL= \frac { e } { \left( R + R _ { h } + r \right) } \cdot \frac { R } { L }

=2(15+5+0)×51= \frac { 2 } { ( 15 + 5 + 0 ) } \times \frac { 5 } { 1 } =0.5 V m=0.005 V cm= 0.5 \frac { \mathrm {~V} } { \mathrm {~m} } = 0.005 \frac { \mathrm {~V} } { \mathrm {~cm} }